Sum and Product of Chords From a Fixed Point

Summary: §§405–409 within the two-intersection framework: has no algebraic solution because carries the irrationality ; relaxing to “more than two intersections” gives infinite-family solutions like concentric-circle pairs. By contrast is satisfied by every circle through , and from each higher order one extracts an infinite family .

Sources: chapter17 §§405–409.

Last updated: 2026-05-11.


Sum constant: impossible (§405)

From two-point-equation-from-fixed-point, the chord-distances satisfy with . Demanding constant means , i.e.

The left side carries the irrationality , which the right side cannot cancel for a polynomial . Hence no algebraic curve has the property across all lines through (when only two intersections are demanded).

This is a genuine no-solution result, not just a technical obstruction: it reflects that constant chord-sum from an interior point is a property of the ellipse from its foci, and any other point fails to inherit the property.

Relaxing to more intersections (§406)

Drop the two-intersection constraint and allow extra intersections coincident with the two at . Then becomes with , and squaring to remove the irrationality gives

The simplest case , (constant) yields

— a complex fourth-order curve that factors as two concentric circles with as common center. Next simplest (, ) gives a sixth-order solvable for :

(Euler is explicit at §406 that these “satisfy the condition” only in the loosened sense — additional intersections beyond are permitted.)

Product constant: the circle (§407)

The product condition is , i.e. , i.e.

Since is non-irrational of degree , the product condition is algebraically clean — no irrationality to remove. The simplest case is , giving

and the general equation specializes to

or with (first-degree),

This is a circle in rectangular coordinates — and §409 notes that no other conic section satisfies the condition, recovering the Euclid-Elements power-of-a-point theorem.

Higher orders (§408)

§408 generalizes: with (in particular a first-degree function), the general equation becomes

Each choice of degree gives a new family. §409 writes out the third-order instance:

equivalent to . From any order, an analogous curve satisfies the constant-product condition.

The asymmetry between sum and product

Why does the sum fail while the product succeeds? The sum-of-roots is odd (degree-1 in ) so it inherits the irrational factor ; the product-of-roots is even (degree-2 in ) and the irrationality cancels. This parity asymmetry — set up in §400 as “P odd, Q even in ” — propagates structurally into the constant-value problems.